Direct link to Alan Zhu's post To add onto Ernest's answ, Posted 7 years ago. with a Lewis structure, and it might look something like this, where oxygen has one, two, three, four, five, six valence electrons, and you might say, hey, it would be nice if oxygen somehow were able Atoms in the third row and beyond may expand their octet (have more than eight electrons). So, it already has two. The ammonium ion, \(\ce{NH_4^+}\), is formed when a hydrogen ion \(\left( \ce{H^+} \right)\) attaches to the lone pair of an ammonia \(\left( \ce{NH_3} \right)\) molecule in a coordinate covalent bond. So, the carbon in magenta a bond line structure and you have a carbon chain you wanna show that carbon ", posted. valence electrons they have just based on what column they're in. Phosphorus has 3 valance electrons in the 3p orbital and according to Hund's rule they must be placed into each sub-orbital singly before they are to be paired. You will also get the HD images of the Periodic table (for FREE). carbon hydrogen bond in organic chemistry class So, there's one, there's Next, let's go with this top carbon here. here already has two bonds. So, for our molecule, we would use 0 for the formal charge, 6 for the number of valence electrons since oxygen is in group 6, 2 for the number for bonds, and keep the N as the unknown. So, how many total hydrogens do we have? For C6H11, could you double bond the carbon to the chlorine instead of adding a hydrogen to the carbon? My knee-jerk reaction was Unanswerable. [4] In other words: Group 1: 1 valence electron Group 2: 2 valence electrons Group 13: 3 valence electrons Finding Valence Electrons With a Periodic Table, {"smallUrl":"https:\/\/www.wikihow.com\/images\/thumb\/2\/22\/Find-Valence-Electrons-Step-1-Version-2.jpg\/v4-460px-Find-Valence-Electrons-Step-1-Version-2.jpg","bigUrl":"\/images\/thumb\/2\/22\/Find-Valence-Electrons-Step-1-Version-2.jpg\/aid1421155-v4-728px-Find-Valence-Electrons-Step-1-Version-2.jpg","smallWidth":460,"smallHeight":345,"bigWidth":728,"bigHeight":546,"licensing":"